2x^2-57x+275=0

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Solution for 2x^2-57x+275=0 equation: 



2x^2-57x+275=0

a = 2; b = -57; c = +275;
Δ = b2-4ac
Δ = -572-4·2·275
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{1049}}{2*2}=\frac{57-\sqrt{1049}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{1049}}{2*2}=\frac{57+\sqrt{1049}}{4}
$

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